9p(p+2)=p+26

Solution for 9p(p+2)=p+26 equation:

9p(p+2)=p+26

We move all terms to the left:

9p(p+2)-(p+26)=0

We multiply parentheses

9p^2+18p-(p+26)=0

We get rid of parentheses

9p^2+18p-p-26=0

We add all the numbers together, and all the variables

9p^2+17p-26=0

a = 9; b = 17; c = -26;
Δ = b2-4ac
Δ = 172-4·9·(-26)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-35}{2*9}=\frac{-52}{18}
=-2+8/9
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+35}{2*9}=\frac{18}{18}
=1
$