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8(5b+2)=8+8(6b+1)
We move all terms to the left:
8(5b+2)-(8+8(6b+1))=0
We multiply parentheses
40b-(8+8(6b+1))+16=0
We calculate terms in parentheses: -(8+8(6b+1)), so:We get rid of parentheses
8+8(6b+1)
determiningTheFunctionDomain 8(6b+1)+8
We multiply parentheses
48b+8+8
We add all the numbers together, and all the variables
48b+16
Back to the equation:
-(48b+16)
40b-48b-16+16=0
We add all the numbers together, and all the variables
-8b=0
b=0/-8
b=0
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