2-6(x-3)+x=3(-5-3x)+40

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Solution for 2-6(x-3)+x=3(-5-3x)+40 equation: 



2-6(x-3)+x=3(-5-3x)+40

We move all terms to the left:

2-6(x-3)+x-(3(-5-3x)+40)=0

We add all the numbers together, and all the variables

-6(x-3)+x-(3(-3x-5)+40)+2=0

We add all the numbers together, and all the variables

x-6(x-3)-(3(-3x-5)+40)+2=0

We multiply parentheses

x-6x-(3(-3x-5)+40)+18+2=0



We calculate terms in parentheses: -(3(-3x-5)+40), so:

3(-3x-5)+40

We multiply parentheses

-9x-15+40

We add all the numbers together, and all the variables

-9x+25

Back to the equation:

-(-9x+25)



We add all the numbers together, and all the variables

-5x-(-9x+25)+20=0

We get rid of parentheses

-5x+9x-25+20=0

We add all the numbers together, and all the variables

4x-5=0

We move all terms containing x to the left, all other terms to the right

4x=5

x=5/4

x=1+1/4

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