6(x2)=36-10x

Solution for 6(x2)=36-10x equation:

6(x2)=36-10x

We move all terms to the left:

6(x2)-(36-10x)=0

We add all the numbers together, and all the variables

6x2-(-10x+36)=0

We add all the numbers together, and all the variables

6x^2-(-10x+36)=0

We get rid of parentheses

6x^2+10x-36=0

a = 6; b = 10; c = -36;
Δ = b2-4ac
Δ = 102-4·6·(-36)
Δ = 964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{964}=\sqrt{4*241}=\sqrt{4}*\sqrt{241}=2\sqrt{241}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{241}}{2*6}=\frac{-10-2\sqrt{241}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{241}}{2*6}=\frac{-10+2\sqrt{241}}{12}
$