8(3r-1)=2r+4(5r+4)

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Solution for 8(3r-1)=2r+4(5r+4) equation: 



8(3r-1)=2r+4(5r+4)

We move all terms to the left:

8(3r-1)-(2r+4(5r+4))=0

We multiply parentheses

24r-(2r+4(5r+4))-8=0



We calculate terms in parentheses: -(2r+4(5r+4)), so:

2r+4(5r+4)

We multiply parentheses

2r+20r+16

We add all the numbers together, and all the variables

22r+16

Back to the equation:

-(22r+16)



We get rid of parentheses

24r-22r-16-8=0

We add all the numbers together, and all the variables

2r-24=0

We move all terms containing r to the left, all other terms to the right

2r=24

r=24/2

r=12

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