7-(y+1)=-2(3-3y)

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Solution for 7-(y+1)=-2(3-3y) equation:



7-(y+1)=-2(3-3y)
We move all terms to the left:
7-(y+1)-(-2(3-3y))=0
We add all the numbers together, and all the variables
-(y+1)-(-2(-3y+3))+7=0
We get rid of parentheses
-y-(-2(-3y+3))-1+7=0
We calculate terms in parentheses: -(-2(-3y+3)), so:
-2(-3y+3)
We multiply parentheses
6y-6
Back to the equation:
-(6y-6)
We add all the numbers together, and all the variables
-1y-(6y-6)+6=0
We get rid of parentheses
-1y-6y+6+6=0
We add all the numbers together, and all the variables
-7y+12=0
We move all terms containing y to the left, all other terms to the right
-7y=-12
y=-12/-7
y=1+5/7

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