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2x+2x+2=4x^2
We move all terms to the left:
2x+2x+2-(4x^2)=0
determiningTheFunctionDomain -4x^2+2x+2x+2=0
We add all the numbers together, and all the variables
-4x^2+4x+2=0
a = -4; b = 4; c = +2;
Δ = b2-4ac
Δ = 42-4·(-4)·2
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{3}}{2*-4}=\frac{-4-4\sqrt{3}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{3}}{2*-4}=\frac{-4+4\sqrt{3}}{-8} $
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