8(2x-5)=15(3x-5)+23

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Solution for 8(2x-5)=15(3x-5)+23 equation: 



8(2x-5)=15(3x-5)+23

We move all terms to the left:

8(2x-5)-(15(3x-5)+23)=0

We multiply parentheses

16x-(15(3x-5)+23)-40=0



We calculate terms in parentheses: -(15(3x-5)+23), so:

15(3x-5)+23

We multiply parentheses

45x-75+23

We add all the numbers together, and all the variables

45x-52

Back to the equation:

-(45x-52)



We get rid of parentheses

16x-45x+52-40=0

We add all the numbers together, and all the variables

-29x+12=0

We move all terms containing x to the left, all other terms to the right

-29x=-12

x=-12/-29

x=12/29

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