18a2+10a=-11a+4

Solution for 18a2+10a=-11a+4 equation:

18a^2+10a=-11a+4

We move all terms to the left:

18a^2+10a-(-11a+4)=0

We get rid of parentheses

18a^2+10a+11a-4=0

We add all the numbers together, and all the variables

18a^2+21a-4=0

a = 18; b = 21; c = -4;
Δ = b2-4ac
Δ = 212-4·18·(-4)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-27}{2*18}=\frac{-48}{36}
=-1+1/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+27}{2*18}=\frac{6}{36}
=1/6
$