(4x-5)-(2x+8)=-6(3x-4)

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Solution for (4x-5)-(2x+8)=-6(3x-4) equation: 



(4x-5)-(2x+8)=-6(3x-4)

We move all terms to the left:

(4x-5)-(2x+8)-(-6(3x-4))=0

We get rid of parentheses

4x-2x-(-6(3x-4))-5-8=0



We calculate terms in parentheses: -(-6(3x-4)), so:

-6(3x-4)

We multiply parentheses

-18x+24

Back to the equation:

-(-18x+24)



We add all the numbers together, and all the variables

2x-(-18x+24)-13=0

We get rid of parentheses

2x+18x-24-13=0

We add all the numbers together, and all the variables

20x-37=0

We move all terms containing x to the left, all other terms to the right

20x=37

x=37/20

x=1+17/20

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