8(2x+2)=3x+8(x-3)

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Solution for 8(2x+2)=3x+8(x-3) equation: 



8(2x+2)=3x+8(x-3)

We move all terms to the left:

8(2x+2)-(3x+8(x-3))=0

We multiply parentheses

16x-(3x+8(x-3))+16=0



We calculate terms in parentheses: -(3x+8(x-3)), so:

3x+8(x-3)

We multiply parentheses

3x+8x-24

We add all the numbers together, and all the variables

11x-24

Back to the equation:

-(11x-24)



We get rid of parentheses

16x-11x+24+16=0

We add all the numbers together, and all the variables

5x+40=0

We move all terms containing x to the left, all other terms to the right

5x=-40

x=-40/5

x=-8

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