1m(2m-3)=4m+66

Solution for 1m(2m-3)=4m+66 equation:

1m(2m-3)=4m+66

We move all terms to the left:

1m(2m-3)-(4m+66)=0

We multiply parentheses

2m^2-3m-(4m+66)=0

We get rid of parentheses

2m^2-3m-4m-66=0

We add all the numbers together, and all the variables

2m^2-7m-66=0

a = 2; b = -7; c = -66;
Δ = b2-4ac
Δ = -72-4·2·(-66)
Δ = 577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{577}}{2*2}=\frac{7-\sqrt{577}}{4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{577}}{2*2}=\frac{7+\sqrt{577}}{4}
$