1m(2m-3)=2m+66

Solution for 1m(2m-3)=2m+66 equation:

1m(2m-3)=2m+66

We move all terms to the left:

1m(2m-3)-(2m+66)=0

We multiply parentheses

2m^2-3m-(2m+66)=0

We get rid of parentheses

2m^2-3m-2m-66=0

We add all the numbers together, and all the variables

2m^2-5m-66=0

a = 2; b = -5; c = -66;
Δ = b2-4ac
Δ = -52-4·2·(-66)
Δ = 553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{553}}{2*2}=\frac{5-\sqrt{553}}{4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{553}}{2*2}=\frac{5+\sqrt{553}}{4}
$