8(1y-7)=-2(1y+3)

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Solution for 8(1y-7)=-2(1y+3) equation: 



8(1y-7)=-2(1y+3)

We move all terms to the left:

8(1y-7)-(-2(1y+3))=0

We add all the numbers together, and all the variables

8(y-7)-(-2(y+3))=0

We multiply parentheses

8y-(-2(y+3))-56=0



We calculate terms in parentheses: -(-2(y+3)), so:

-2(y+3)

We multiply parentheses

-2y-6

Back to the equation:

-(-2y-6)



We get rid of parentheses

8y+2y+6-56=0

We add all the numbers together, and all the variables

10y-50=0

We move all terms containing y to the left, all other terms to the right

10y=50

y=50/10

y=5

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