6(y+42)=12

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Solution for 6(y+42)=12 equation: 



6(y+42)=12

We move all terms to the left:

6(y+42)-(12)=0

We multiply parentheses

6y+252-12=0

We add all the numbers together, and all the variables

6y+240=0

We move all terms containing y to the left, all other terms to the right

6y=-240

y=-240/6

y=-40

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