5y+(3y-1)=11y-(y+2)

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Solution for 5y+(3y-1)=11y-(y+2) equation: 



5y+(3y-1)=11y-(y+2)

We move all terms to the left:

5y+(3y-1)-(11y-(y+2))=0

We get rid of parentheses

5y+3y-(11y-(y+2))-1=0



We calculate terms in parentheses: -(11y-(y+2)), so:

11y-(y+2)

We get rid of parentheses

11y-y-2

We add all the numbers together, and all the variables

10y-2

Back to the equation:

-(10y-2)



We add all the numbers together, and all the variables

8y-(10y-2)-1=0

We get rid of parentheses

8y-10y+2-1=0

We add all the numbers together, and all the variables

-2y+1=0

We move all terms containing y to the left, all other terms to the right

-2y=-1

y=-1/-2

y=1/2

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