8(1-x)=8(1+4x)

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Solution for 8(1-x)=8(1+4x) equation: 



8(1-x)=8(1+4x)

We move all terms to the left:

8(1-x)-(8(1+4x))=0

We add all the numbers together, and all the variables

8(-1x+1)-(8(4x+1))=0

We multiply parentheses

-8x-(8(4x+1))+8=0



We calculate terms in parentheses: -(8(4x+1)), so:

8(4x+1)

We multiply parentheses

32x+8

Back to the equation:

-(32x+8)



We get rid of parentheses

-8x-32x-8+8=0

We add all the numbers together, and all the variables

-40x=0

x=0/-40

x=0

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