10((2b+1)/4)-4b=3

Solution for 10((2b+1)/4)-4b=3 equation:

10((2b+1)/4)-4b=3

We move all terms to the left:

10((2b+1)/4)-4b-(3)=0

We add all the numbers together, and all the variables

-4b+10((2b+1)/4)-3=0

We multiply all the terms by the denominator


-4b*4)+10((2b+1)-3*4)=0

We add all the numbers together, and all the variables

-4b*4)+10((2b+1)=0

Wy multiply elements

-16b^2=0

a = -16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-16)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{-32}=0$