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3x(x+8)=48
We move all terms to the left:
3x(x+8)-(48)=0
We multiply parentheses
3x^2+24x-48=0
a = 3; b = 24; c = -48;
Δ = b2-4ac
Δ = 242-4·3·(-48)
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24\sqrt{2}}{2*3}=\frac{-24-24\sqrt{2}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24\sqrt{2}}{2*3}=\frac{-24+24\sqrt{2}}{6} $
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