2/3y-4=1/6y+5

Solution for 2/3y-4=1/6y+5 equation:

2/3y-4=1/6y+5

We move all terms to the left:

2/3y-4-(1/6y+5)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



Domain of the equation: 6y+5)!=0

y∈R


We get rid of parentheses

2/3y-1/6y-5-4=0

We calculate fractions


12y/18y^2+(-3y)/18y^2-5-4=0

We add all the numbers together, and all the variables

12y/18y^2+(-3y)/18y^2-9=0

We multiply all the terms by the denominator


12y+(-3y)-9*18y^2=0

Wy multiply elements

-162y^2+12y+(-3y)=0

We get rid of parentheses

-162y^2+12y-3y=0

We add all the numbers together, and all the variables

-162y^2+9y=0

a = -162; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-162)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-162}=\frac{-18}{-324}
=1/18
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-162}=\frac{0}{-324}
=0
$