2(2x-2)-4=2(x-5)+12

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Solution for 2(2x-2)-4=2(x-5)+12 equation: 



2(2x-2)-4=2(x-5)+12

We move all terms to the left:

2(2x-2)-4-(2(x-5)+12)=0

We multiply parentheses

4x-(2(x-5)+12)-4-4=0



We calculate terms in parentheses: -(2(x-5)+12), so:

2(x-5)+12

We multiply parentheses

2x-10+12

We add all the numbers together, and all the variables

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

4x-(2x+2)-8=0

We get rid of parentheses

4x-2x-2-8=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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