7y+3(y-3)=5(y+1)-3

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Solution for 7y+3(y-3)=5(y+1)-3 equation: 



7y+3(y-3)=5(y+1)-3

We move all terms to the left:

7y+3(y-3)-(5(y+1)-3)=0

We multiply parentheses

7y+3y-(5(y+1)-3)-9=0



We calculate terms in parentheses: -(5(y+1)-3), so:

5(y+1)-3

We multiply parentheses

5y+5-3

We add all the numbers together, and all the variables

5y+2

Back to the equation:

-(5y+2)



We add all the numbers together, and all the variables

10y-(5y+2)-9=0

We get rid of parentheses

10y-5y-2-9=0

We add all the numbers together, and all the variables

5y-11=0

We move all terms containing y to the left, all other terms to the right

5y=11

y=11/5

y=2+1/5

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