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4(x-1)+3=2x+2(-1+x)
We move all terms to the left:
4(x-1)+3-(2x+2(-1+x))=0
We add all the numbers together, and all the variables
4(x-1)-(2x+2(x-1))+3=0
We multiply parentheses
4x-(2x+2(x-1))-4+3=0
We calculate terms in parentheses: -(2x+2(x-1)), so:We add all the numbers together, and all the variables
2x+2(x-1)
We multiply parentheses
2x+2x-2
We add all the numbers together, and all the variables
4x-2
Back to the equation:
-(4x-2)
4x-(4x-2)-1=0
We get rid of parentheses
4x-4x+2-1=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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