5x-4/3x=22

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Solution for 5x-4/3x=22 equation:



5x-4/3x=22
We move all terms to the left:
5x-4/3x-(22)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We multiply all the terms by the denominator
5x*3x-22*3x-4=0
Wy multiply elements
15x^2-66x-4=0
a = 15; b = -66; c = -4;
Δ = b2-4ac
Δ = -662-4·15·(-4)
Δ = 4596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{4596}=\sqrt{4*1149}=\sqrt{4}*\sqrt{1149}=2\sqrt{1149}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-2\sqrt{1149}}{2*15}=\frac{66-2\sqrt{1149}}{30} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+2\sqrt{1149}}{2*15}=\frac{66+2\sqrt{1149}}{30} $

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