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9-51/2x-3(-2x+1)=x
We move all terms to the left:
9-51/2x-3(-2x+1)-(x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-1x-51/2x-3(-2x+1)+9=0
We multiply parentheses
-1x-51/2x+6x-3+9=0
We multiply all the terms by the denominator
-1x*2x+6x*2x-3*2x+9*2x-51=0
Wy multiply elements
-2x^2+12x^2-6x+18x-51=0
We add all the numbers together, and all the variables
10x^2+12x-51=0
a = 10; b = 12; c = -51;
Δ = b2-4ac
Δ = 122-4·10·(-51)
Δ = 2184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2184}=\sqrt{4*546}=\sqrt{4}*\sqrt{546}=2\sqrt{546}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{546}}{2*10}=\frac{-12-2\sqrt{546}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{546}}{2*10}=\frac{-12+2\sqrt{546}}{20} $
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