7y+2=3(2y-1)

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Solution for 7y+2=3(2y-1) equation: 



7y+2=3(2y-1)

We move all terms to the left:

7y+2-(3(2y-1))=0



We calculate terms in parentheses: -(3(2y-1)), so:

3(2y-1)

We multiply parentheses

6y-3

Back to the equation:

-(6y-3)



We get rid of parentheses

7y-6y+3+2=0

We add all the numbers together, and all the variables

y+5=0

We move all terms containing y to the left, all other terms to the right

y=-5

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