7+2(x-5)=3(x-4)

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Solution for 7+2(x-5)=3(x-4) equation: 



7+2(x-5)=3(x-4)

We move all terms to the left:

7+2(x-5)-(3(x-4))=0

We multiply parentheses

2x-(3(x-4))-10+7=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

2x-(3x-12)-3=0

We get rid of parentheses

2x-3x+12-3=0

We add all the numbers together, and all the variables

-1x+9=0

We move all terms containing x to the left, all other terms to the right

-x=-9

x=-9/-1

x=+9

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