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+1=1/2(Y+4)
We move all terms to the left:
+1-(1/2(Y+4))=0
Domain of the equation: 2(Y+4))!=0We multiply all the terms by the denominator
Y∈R
-(1+1*2(Y+4))=0
We calculate terms in parentheses: -(1+1*2(Y+4)), so:
1+1*2(Y+4)
determiningTheFunctionDomain 1*2(Y+4)+1
Wy multiply elements
2Y(Y+1
Back to the equation:
-(2Y(Y+1)
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| -5v+3(v+8)=18 | | -5u+2(u-2)=-25 | | 8=2y+8(y+6) | | 2w+7(w-8)=-29 | | 30=6(x+7)-8x | | -4=2x-3/4-7x-4/8 | | 2x-30+60+2x=180 | | x^2-6.4x-6=0 | | 40x-1.5=9x+1.5 | | 2m/5=2/5m-4 | | a+1.25=2a- | | 180=x+4x-2 | | 4x^2+7x+7=9 | | 180=4x-2 | | 8x-20=-10-7x | | -15-2n=-65 | | 7+2(x-5)=3(x-4) | | -12-3(x-4)=-3x | | -(4x+8)=12 | | 4-2(x+6)=8 | | 44=2(4x-5)+x | | -1(4x+8)=12 | | 187=13-y | | 180=8+16x+18x-6 | | 180=x+128+120 | | (6x-9)=(2x-19) | | -2+5x+12=20 | | 6=-5x+16 | | 7-3y=36 | | 5-6(1/2x-8)=76 | | 41x-3=90 | | 9v-27=v+43+4v |