7x-4(3x-42)=133

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Solution for 7x-4(3x-42)=133 equation:



7x-4(3x-42)=133
We move all terms to the left:
7x-4(3x-42)-(133)=0
We multiply parentheses
7x-12x+168-133=0
We add all the numbers together, and all the variables
-5x+35=0
We move all terms containing x to the left, all other terms to the right
-5x=-35
x=-35/-5
x=+7

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