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(2x/(x+5))+(3/(x+9))=1
We move all terms to the left:
(2x/(x+5))+(3/(x+9))-(1)=0
Domain of the equation: (x+5))!=0
x∈R
Domain of the equation: (x+9))!=0We calculate fractions
x∈R
(2x^2+18x)/((x+5))*x+(3x+15)/((x+5))*x-1=0
We multiply all the terms by the denominator
(2x^2+18x)+(3x+15)-1*((x+5))*x=0
We get rid of parentheses
2x^2+18x+3x-1*((x+5))*x+15=0
We add all the numbers together, and all the variables
2x^2+21x-1*((x+5))*x+15=0
We move all terms containing x to the left, all other terms to the right
2x^2+21x-1*((x+5))*x=-15
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