18(t-2)+3t=7(3t+2)-10

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Solution for 18(t-2)+3t=7(3t+2)-10 equation: 



18(t-2)+3t=7(3t+2)-10

We move all terms to the left:

18(t-2)+3t-(7(3t+2)-10)=0

We add all the numbers together, and all the variables

3t+18(t-2)-(7(3t+2)-10)=0

We multiply parentheses

3t+18t-(7(3t+2)-10)-36=0



We calculate terms in parentheses: -(7(3t+2)-10), so:

7(3t+2)-10

We multiply parentheses

21t+14-10

We add all the numbers together, and all the variables

21t+4

Back to the equation:

-(21t+4)



We add all the numbers together, and all the variables

21t-(21t+4)-36=0

We get rid of parentheses

21t-21t-4-36=0

We add all the numbers together, and all the variables

-40!=0

There is no solution for this equation

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