7x-3x+7=3(x-4)+2

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Solution for 7x-3x+7=3(x-4)+2 equation: 



7x-3x+7=3(x-4)+2

We move all terms to the left:

7x-3x+7-(3(x-4)+2)=0

We add all the numbers together, and all the variables

4x-(3(x-4)+2)+7=0



We calculate terms in parentheses: -(3(x-4)+2), so:

3(x-4)+2

We multiply parentheses

3x-12+2

We add all the numbers together, and all the variables

3x-10

Back to the equation:

-(3x-10)



We get rid of parentheses

4x-3x+10+7=0

We add all the numbers together, and all the variables

x+17=0

We move all terms containing x to the left, all other terms to the right

x=-17

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