(19-2x)(28-2x)=442

Solution for (19-2x)(28-2x)=442 equation:

(19-2x)(28-2x)=442

We move all terms to the left:

(19-2x)(28-2x)-(442)=0

We add all the numbers together, and all the variables

(-2x+19)(-2x+28)-442=0

We multiply parentheses ..

(+4x^2-56x-38x+532)-442=0

We get rid of parentheses

4x^2-56x-38x+532-442=0

We add all the numbers together, and all the variables

4x^2-94x+90=0

a = 4; b = -94; c = +90;
Δ = b2-4ac
Δ = -942-4·4·90
Δ = 7396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7396}=86$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-94)-86}{2*4}=\frac{8}{8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-94)+86}{2*4}=\frac{180}{8}
=22+1/2
$