(19x-2x)(28-2x)=442

Solution for (19x-2x)(28-2x)=442 equation:

(19x-2x)(28-2x)=442

We move all terms to the left:

(19x-2x)(28-2x)-(442)=0

We add all the numbers together, and all the variables

(+17x)(-2x+28)-442=0

We multiply parentheses ..

(-34x^2+476x)-442=0

We get rid of parentheses

-34x^2+476x-442=0

a = -34; b = 476; c = -442;
Δ = b2-4ac
Δ = 4762-4·(-34)·(-442)
Δ = 166464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{166464}=408$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(476)-408}{2*-34}=\frac{-884}{-68}
=+13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(476)+408}{2*-34}=\frac{-68}{-68}
=1
$