7x-3(2x-5)=6(2+3x)-32

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Solution for 7x-3(2x-5)=6(2+3x)-32 equation: 



7x-3(2x-5)=6(2+3x)-32

We move all terms to the left:

7x-3(2x-5)-(6(2+3x)-32)=0

We add all the numbers together, and all the variables

7x-3(2x-5)-(6(3x+2)-32)=0

We multiply parentheses

7x-6x-(6(3x+2)-32)+15=0



We calculate terms in parentheses: -(6(3x+2)-32), so:

6(3x+2)-32

We multiply parentheses

18x+12-32

We add all the numbers together, and all the variables

18x-20

Back to the equation:

-(18x-20)



We add all the numbers together, and all the variables

x-(18x-20)+15=0

We get rid of parentheses

x-18x+20+15=0

We add all the numbers together, and all the variables

-17x+35=0

We move all terms containing x to the left, all other terms to the right

-17x=-35

x=-35/-17

x=2+1/17

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