9(4x+3)=5(2-x)+x-2

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Solution for 9(4x+3)=5(2-x)+x-2 equation: 



9(4x+3)=5(2-x)+x-2

We move all terms to the left:

9(4x+3)-(5(2-x)+x-2)=0

We add all the numbers together, and all the variables

9(4x+3)-(5(-1x+2)+x-2)=0

We multiply parentheses

36x-(5(-1x+2)+x-2)+27=0



We calculate terms in parentheses: -(5(-1x+2)+x-2), so:

5(-1x+2)+x-2

We add all the numbers together, and all the variables

x+5(-1x+2)-2

We multiply parentheses

x-5x+10-2

We add all the numbers together, and all the variables

-4x+8

Back to the equation:

-(-4x+8)



We get rid of parentheses

36x+4x-8+27=0

We add all the numbers together, and all the variables

40x+19=0

We move all terms containing x to the left, all other terms to the right

40x=-19

x=-19/40

x=-19/40

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