6x-2(x+3)=5(2x-1)=0

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Solution for 6x-2(x+3)=5(2x-1)=0 equation: 



6x-2(x+3)=5(2x-1)=0

We move all terms to the left:

6x-2(x+3)-(5(2x-1))=0

We multiply parentheses

6x-2x-(5(2x-1))-6=0



We calculate terms in parentheses: -(5(2x-1)), so:

5(2x-1)

We multiply parentheses

10x-5

Back to the equation:

-(10x-5)



We add all the numbers together, and all the variables

4x-(10x-5)-6=0

We get rid of parentheses

4x-10x+5-6=0

We add all the numbers together, and all the variables

-6x-1=0

We move all terms containing x to the left, all other terms to the right

-6x=1

x=1/-6

x=-1/6

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