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7x(7x+5)=4875
We move all terms to the left:
7x(7x+5)-(4875)=0
We multiply parentheses
49x^2+35x-4875=0
a = 49; b = 35; c = -4875;
Δ = b2-4ac
Δ = 352-4·49·(-4875)
Δ = 956725
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{956725}=\sqrt{1225*781}=\sqrt{1225}*\sqrt{781}=35\sqrt{781}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35\sqrt{781}}{2*49}=\frac{-35-35\sqrt{781}}{98} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35\sqrt{781}}{2*49}=\frac{-35+35\sqrt{781}}{98} $
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