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1/5x+10+3x/x+2=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
1/5x+3x/x+12=0
We calculate fractions
15x^2/5x^2+x/5x^2+12=0
We multiply all the terms by the denominator
15x^2+x+12*5x^2=0
Wy multiply elements
15x^2+60x^2+x=0
We add all the numbers together, and all the variables
75x^2+x=0
a = 75; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·75·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*75}=\frac{-2}{150} =-1/75 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*75}=\frac{0}{150} =0 $
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