(8x-1)(6x+1)=0

Solution for (8x-1)(6x+1)=0 equation:

(8x-1)(6x+1)=0

We multiply parentheses ..

(+48x^2+8x-6x-1)=0

We get rid of parentheses

48x^2+8x-6x-1=0

We add all the numbers together, and all the variables

48x^2+2x-1=0

a = 48; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·48·(-1)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-14}{2*48}=\frac{-16}{96}
=-1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+14}{2*48}=\frac{12}{96}
=1/8
$