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7x(4x-3)=2x-5
We move all terms to the left:
7x(4x-3)-(2x-5)=0
We multiply parentheses
28x^2-21x-(2x-5)=0
We get rid of parentheses
28x^2-21x-2x+5=0
We add all the numbers together, and all the variables
28x^2-23x+5=0
a = 28; b = -23; c = +5;
Δ = b2-4ac
Δ = -232-4·28·5
Δ = -31
Delta is less than zero, so there is no solution for the equation
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