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7(x+4)3x+2=6
We move all terms to the left:
7(x+4)3x+2-(6)=0
We add all the numbers together, and all the variables
7(x+4)3x-4=0
We multiply parentheses
21x^2+84x-4=0
a = 21; b = 84; c = -4;
Δ = b2-4ac
Δ = 842-4·21·(-4)
Δ = 7392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7392}=\sqrt{16*462}=\sqrt{16}*\sqrt{462}=4\sqrt{462}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-4\sqrt{462}}{2*21}=\frac{-84-4\sqrt{462}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+4\sqrt{462}}{2*21}=\frac{-84+4\sqrt{462}}{42} $
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