(2y+6)=(8y+102)

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Solution for (2y+6)=(8y+102) equation: 



(2y+6)=(8y+102)

We move all terms to the left:

(2y+6)-((8y+102))=0

We get rid of parentheses

2y-((8y+102))+6=0



We calculate terms in parentheses: -((8y+102)), so:

(8y+102)

We get rid of parentheses

8y+102

Back to the equation:

-(8y+102)



We get rid of parentheses

2y-8y-102+6=0

We add all the numbers together, and all the variables

-6y-96=0

We move all terms containing y to the left, all other terms to the right

-6y=96

y=96/-6

y=-16

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