-4(v+1)=4v-3+5(2v+1)

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Solution for -4(v+1)=4v-3+5(2v+1) equation: 



-4(v+1)=4v-3+5(2v+1)

We move all terms to the left:

-4(v+1)-(4v-3+5(2v+1))=0

We multiply parentheses

-4v-(4v-3+5(2v+1))-4=0



We calculate terms in parentheses: -(4v-3+5(2v+1)), so:

4v-3+5(2v+1)

determiningTheFunctionDomain
4v+5(2v+1)-3

We multiply parentheses

4v+10v+5-3

We add all the numbers together, and all the variables

14v+2

Back to the equation:

-(14v+2)



We get rid of parentheses

-4v-14v-2-4=0

We add all the numbers together, and all the variables

-18v-6=0

We move all terms containing v to the left, all other terms to the right

-18v=6

v=6/-18

v=-1/3

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