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7x(3x-14)=3x+12
We move all terms to the left:
7x(3x-14)-(3x+12)=0
We multiply parentheses
21x^2-98x-(3x+12)=0
We get rid of parentheses
21x^2-98x-3x-12=0
We add all the numbers together, and all the variables
21x^2-101x-12=0
a = 21; b = -101; c = -12;
Δ = b2-4ac
Δ = -1012-4·21·(-12)
Δ = 11209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-101)-\sqrt{11209}}{2*21}=\frac{101-\sqrt{11209}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-101)+\sqrt{11209}}{2*21}=\frac{101+\sqrt{11209}}{42} $
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