(3x-7)-(5x-2)=1-4x-5(6-2x)

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Solution for (3x-7)-(5x-2)=1-4x-5(6-2x) equation: 



(3x-7)-(5x-2)=1-4x-5(6-2x)

We move all terms to the left:

(3x-7)-(5x-2)-(1-4x-5(6-2x))=0

We add all the numbers together, and all the variables

(3x-7)-(5x-2)-(1-4x-5(-2x+6))=0

We get rid of parentheses

3x-5x-(1-4x-5(-2x+6))-7+2=0



We calculate terms in parentheses: -(1-4x-5(-2x+6)), so:

1-4x-5(-2x+6)

determiningTheFunctionDomain
-4x-5(-2x+6)+1

We multiply parentheses

-4x+10x-30+1

We add all the numbers together, and all the variables

6x-29

Back to the equation:

-(6x-29)



We add all the numbers together, and all the variables

-2x-(6x-29)-5=0

We get rid of parentheses

-2x-6x+29-5=0

We add all the numbers together, and all the variables

-8x+24=0

We move all terms containing x to the left, all other terms to the right

-8x=-24

x=-24/-8

x=+3

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