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7x(2x-800)=0
We multiply parentheses
14x^2-5600x=0
a = 14; b = -5600; c = 0;
Δ = b2-4ac
Δ = -56002-4·14·0
Δ = 31360000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{31360000}=5600$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5600)-5600}{2*14}=\frac{0}{28} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5600)+5600}{2*14}=\frac{11200}{28} =400 $
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