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3(x-5)=8(2-x)
We move all terms to the left:
3(x-5)-(8(2-x))=0
We add all the numbers together, and all the variables
3(x-5)-(8(-1x+2))=0
We multiply parentheses
3x-(8(-1x+2))-15=0
We calculate terms in parentheses: -(8(-1x+2)), so:We get rid of parentheses
8(-1x+2)
We multiply parentheses
-8x+16
Back to the equation:
-(-8x+16)
3x+8x-16-15=0
We add all the numbers together, and all the variables
11x-31=0
We move all terms containing x to the left, all other terms to the right
11x=31
x=31/11
x=2+9/11
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