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3/(x-2)=6/(x+3)
We move all terms to the left:
3/(x-2)-(6/(x+3))=0
Domain of the equation: (x-2)!=0
We move all terms containing x to the left, all other terms to the right
x!=2
x∈R
Domain of the equation: (x+3))!=0We calculate fractions
x∈R
3x/((x-2)*(x+3)))+(-(6*(x-2))/((x-2)*(x+3)))=0
We calculate terms in parentheses: -(6*(x-2))/((x-2)*(x+3))), so:We add all the numbers together, and all the variables
6*(x-2))/((x-2)*(x+3))
We multiply all the terms by the denominator
6*(x-2))
We multiply parentheses
6x+
We add all the numbers together, and all the variables
6x
Back to the equation:
-(6x)
-6x+3x/((x-2)*(x+3)))+(=0
We multiply all the terms by the denominator
-6x*((x-2)*(x+3)))+(+3x=0
We add all the numbers together, and all the variables
3x-6x*((x-2)*(x+3)))+(=0
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