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7m^2-28m-84=0
a = 7; b = -28; c = -84;
Δ = b2-4ac
Δ = -282-4·7·(-84)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-56}{2*7}=\frac{-28}{14} =-2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+56}{2*7}=\frac{84}{14} =6 $
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